4 billion if statements (2023)
566 points
6 days ago
| 53 comments
| andreasjhkarlsson.github.io
| HN
xnorswap
8 hours ago
[-]
This is time efficient* but rather wasteful of space.

The best way to save space is to use a Bloom Filter.

If we capture all the even numbers, that would sadly only give us "Definitely not Even" or "Maybe Even".

But for just the cost of doubling our space, we can use two Bloom filters!

So we can construct one bloom filter capturing even numbers, and another bloom filter capturing odd numbers.

Now we have "Definitely not Even" and "Maybe Even" but also "Definitely not Odd" and "Maybe Odd".

In this manner, we can use the "evens" filter to find the odd numbers and the "odds" filter to find the even numbers.

Having done this, we'll be left with just a handful of unlucky numbers that are recorded as both "Maybe even" and "Maybe odd". These will surely be few enough in number that we can special case these in our if/else block.

The filters as a first-pass will save gigabytes of memory!

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gopalv
7 hours ago
[-]
> But for just the cost of doubling our space, we can use two Bloom filters!

We can optimize the hash function to make it more space efficient.

Instead of using remainders to locate filter positions, we can use a mersenne prime number mask (like say 31), but in this case I have a feeling the best hash function to use would be to mask with (2^1)-1.

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AlotOfReading
6 hours ago
[-]
This produced strange results on my ternary computer. I had to use a recursive popcnt instead.
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piersadrian
4 hours ago
[-]
this is my new favorite comment on this cursed website
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nixpulvis
7 hours ago
[-]
How is this time efficient at all? It takes upwards of 40 seconds to compute on large 32bit values.

It's a joke post with some interesting bits and details.

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xnorswap
7 hours ago
[-]
It's a constant number of lookups, and all good Computer Scientists know that it is therefore an O(1) algorithm.

It is hard to imagine better efficiency than O(1)!

Indeed we could improve it further by performing all evaluations even when we find the answer earlier, ensuring it is a true Constant Time algorithm, safe for use in cryptography.

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nixpulvis
7 hours ago
[-]
> This is time efficient* but rather wasteful of space.

You're saying that the blog's solution is time efficient. Which it is not. Your solution may be O(1) but it is also not efficient. As I'm sure you are aware.

I can tell you a practical solution which is also O(1) and takes up maybe 2 or 3 instructions of program code and no extra memory at all.

`x & 1` or `x % 2 != 0`

This blog post was taking a joke and running with it. And your comment is in that spirit as well, I just wanted to point out that it's by no means time efficient when we have 2s or 1s complement numbers which make this algorithm trivial.

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icambron
7 hours ago
[-]
You need to read their entire comment as a joke.
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nixpulvis
7 hours ago
[-]
I guess I should have been more clear that I was just pointing out the obvious in case some confused reader missed the joke.

lol

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kbelder
6 hours ago
[-]
Which was also obvious, but maybe also needed pointing out, which says something about online discussion. Something obvious, probably.
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ricardo81
6 hours ago
[-]
explaining the joke spoils the joke, such is social convention.
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nixpulvis
5 hours ago
[-]
Forgive me for not being funny.
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henrikschroder
1 hour ago
[-]
> I just wanted to point out that

We already know. Everybody knows. That's the joke. There's no need to point out anything.

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Sohcahtoa82
6 hours ago
[-]
How are you able to recognize a joke post but not a joke comment?
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nixpulvis
5 hours ago
[-]
I may have missed the * meaning. I got that the bloom filter was an extension of the joke as I mentioned below. I was just clarifying in case someone else missed the joke.
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uplifter
5 hours ago
[-]
You're absolutely right. The obvious solution would have been to create a boolean table containing all the pre-computed answers, and then simply use the integer you are testing as the index of the correct answer in memory. Now your isEven code is just a simple array lookup! Such an obvious improvement, I can't believe the OP didn't see it.

And with a little extra work you can shrink the whole table's size in memory by a factor of eight, but I'll leave that as an exercise for the interested reader.

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mandarax8
3 hours ago
[-]
Maybe we can even find some correlation in the bit pattern of the input and the Boolean table!
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jiggawatts
2 hours ago
[-]
If the "exercise" is to strictly rely on if-else statements, then the obvious speedup is to perform a binary search instead of a linear one. The result would still be horrifically space inefficient, but the speed would be roughly the time it takes to load 32x 4KB pages randomly from disk (the article memory-mapped the file). On a modern SSD a random read is 20 microseconds, so that's less than a millisecond for an even/odd check!

"That's good enough, ship it to production. We'll optimise it later."

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Maxatar
7 hours ago
[-]
The comment you're replying to is also a joke, with some interesting bits and details.
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nixpulvis
5 hours ago
[-]
I think I'll just avoid commenting on jokes from now on.
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nrhrjrjrjtntbt
2 hours ago
[-]
r/whoosh
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ZeroConcerns
12 hours ago
[-]
Ah, yes, exactly the pointless diversion I needed for my lunch break. For science: generating a C# switch statement for similar purposes took 7 minutes on similar-ish hardware, but the resulting 99.2GB file could not be opened or compiled ('Stream is too long'), which was slightly disappointing.

Optimization efforts included increasing the internal buffer size of the StreamWriter used to create the source code: this reduced the runtime to around 6 minutes, as well as running a non-debug build, as it was observed that the poor Visual Studio metrics gathering process was contributing significantly to disk activity as well, but that ultimately didn't matter much. So, ehhm, yes, good job on that I guess?

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afandian
11 hours ago
[-]
Isn't the obvious thing to generate different classes for different ranges over the input? Then the classes could be loaded lazily.

And if you then make the ranges tree-shaped you get logarithmic complexity, which massively cuts down the O(n) of the rather naive chained `if` statements.

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opticfluorine
10 hours ago
[-]
I wonder if you could generate it via a Roslyn incremental source generator instead of as a file to bypass this limit. I'm guessing not, but it does sound like fun.
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tkapin
8 hours ago
[-]
You can totally use source generators for that.
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xnorswap
4 hours ago
[-]
You're only allowed up to 65535 locals, but this includes hidden locals, which the compiler adds if you're compiling in debug mode.

So you have to make sure to compile only in release mode just to get to 16 bits.

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jiggawatts
2 hours ago
[-]
To match the article, you'd want to directly emit the Intermediate Language (IL) tokens with something like this: https://learn.microsoft.com/en-us/dotnet/api/system.reflecti...

I haven't found any authoritative source, but I strongly suspect that the .NET bytecode format has 32-bit limits all over the place. Maaaybe you could break up the code into functions less than 1 GB in size and then chain them together.

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billforsternz
1 hour ago
[-]
I know it's silly, but I just want to fix his first version with the minimum possible changes;

  /* Copyright 2023. All unauthorized distribution of this source code
     will be persecuted to the fullest extent of the law*/
  #include <stdio.h>
  #include <stdint.h>
  #include <string.h>
  int main(int argc, char* argv[])
  {
      uint8_t number = argc>1 ? argv[1][strlen(argv[1])-1]-'0' : printf("Usage: odd-or-even number\n");
      if (number == 0)
          printf("even\n");
      if (number == 1)
          printf("odd\n");
      if (number == 2)
          printf("even\n");
      if (number == 3)
          printf("odd\n");
      if (number == 4)
          printf("even\n");
      if (number == 5)
          printf("odd\n");
      if (number == 6)
          printf("even\n");
      if (number == 7)
          printf("odd\n");
      if (number == 8)
          printf("even\n");
      if (number == 9)
          printf("odd\n");
      if (number == 10)
          printf("even\n");
  }
This way it basically works. It's a shame that it doesn't call out a non numeric argument but that's about the only problem. It relies on a trick, printf() returns the number of characters printed, so the error message string needs to be longer than 10.
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pcthrowaway
21 minutes ago
[-]
Wouldn't using elif for all comparisons after the first improve performance?

Or is the performance considered worse because it becomes O(n) (where n < MAX_UINT) vs. constant time ( O(MAX_UINT) )

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mft_
10 hours ago
[-]
Similar humour if opposite directions to an old favourite: https://joelgrus.com/2016/05/23/fizz-buzz-in-tensorflow/
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thih9
9 hours ago
[-]
I expected some job interview meme[1][2] but I did not know this one and it looks like a real story too! Thanks for sharing, that was a fun read.

[1]: https://aphyr.com/posts/342-typing-the-technical-interview

[2]: https://www.richard-towers.com/2023/03/11/typescripting-the-...

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waisbrot
7 hours ago
[-]
I love the Aphyr posts.

> “Can I use any language?” > > “Sure.” > > Move quickly, before he realizes his mistake.

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kayge
7 hours ago
[-]
> any value over 2^31 seems to give random results.

Wow he really lucked out... On his way to perfecting a fully functioning and performant Even/Odd Detector, he stumbled upon a fully functioning and performant Coin Flip Simulator!

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thedougd
7 hours ago
[-]
I took an ASIC design class in college, unfortunately with a heavy course load that didn't allow me to focus on it. For our final project we were given a numbered dictionary and asked to design a chip that would accept the characters on a 7 bit interface (ASCII), one character per clock cycle and output the dictionary number on an output interface but I can't remember how wide. We were graded on the size of the resulting ASIC and how many clock cycles it took from the last character in to the number on the output.

I started designing my modules, a ROM, a register with a ROM pointer, etc, etc, writing the Verilog and working out the clock sync between modules. Then I got 'lazy' and wrote a trie tree like implementation in Java, and have it spit out the whole tree in Verilog. It worked and just one clock cycle after the last letter my number would output. Fastest in the class! Also the most number of gates in the class. Surprised I got a 90 grade given I didn't use any of the advanced ASIC design the class taught. The TA didn't know what the hell they were looking at.

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weli
7 hours ago
[-]
Yep! Something a bit counterintuitive on circuit design is that dedicated transistors will always beat reusing existing components. If we do reuse existing components like ALUs, multipliers, or state machines, we save on chip area but pay the penalty in clock cycles. Your approach was the extreme version of this tradeoff. You essentially unrolled the entire dictionary lookup into pure combinatorial logic (well, with registers for the input characters). One clock cycle latency because you weren't doing any sequential searching, comparing, or state machine transitions just racing electrons through logic gates.
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retrac
5 hours ago
[-]
It's akin to a compiler unrolling a loop. Uses more RAM (area) but fewer cycles to execute. Hardware synthesis uses many of the same techniques as compilers use to optimize code.

It's a common pitfall for those learning hardware description languages like Verilog, when they think about them like programming languages. If you go "if (calc) res <= a * b;" If res is 32 bits wide then you have instantiated a 32 bit fast multiplier circuit dedicated just to that one operation. This is often not what was intended.

Despite how leaning on the analogy too closely can mislead in that way, the analogy between hardware and software is not a shallow one. A combinatorial circuit is akin to the pure function of functional programming. Anything that can be described as a pure function working on fixed integers or floating point or other discrete data types, can be transformed into a combinatorial circuit. And there are algorithms to do so automatically and often with reasonable efficiency.

Free software synthesis has come a long way in recent years, by the way. There's even several hobbyist projects that can take VHDL or Verilog and produce layouts using TTL chips or even discrete transistor logic with automatic circuit board layout. You can now compile your code directly to circuit board copper masks and a part list.

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_kst_
2 hours ago
[-]
The author missed an opportunity for a much shorter solution for the given problem statement.

    // Check whether a number is odd or even.

    #include <stdio.h>
    #include <stdlib.h>
    #include <stdbool.h>

    static bool is_odd_or_even(unsigned long num) {
        return true;
    }

    int main(int argc, char **argv) {
        const unsigned long num = strtoul(argv[1], NULL, 10);
        printf("%lu is %s odd or even\n",
               num,
               is_odd_or_even(num) ? "is" : "is not");
    }
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niccl
2 hours ago
[-]
Brilliant! Mr Boole would love this
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blauditore
9 hours ago
[-]
This could be obviously done with much less code: Just add "if"s for all even number, and at the end just return "odd" if none of the evens matched. 50% less code!

Or even simpler: If it's 0, return "even". If not, do a recursive call to n-1, if that equals "even", return "odd", otherwise return "even".

But the best way is probably to just use a library. Yes, 500MB of additional dependencies, but then it's a one-liner.

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majkinetor
9 hours ago
[-]
But then, even numbers will have the worst possible performance.
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bobbylarrybobby
4 hours ago
[-]
You brought up an important opportunity for optimization. If you know the distribution of your data, it may make more sense to implement it in terms of the odd numbers and leave even numbers as the fallback. It's important to profile with a realistic distribution of data to make sure you're targeting the correct parity of numbers.
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IncreasePosts
7 hours ago
[-]
Good point. Have two programs - one checking every even number and returning odd of not even. And then have a program checking every odd number and returning even if not. Then, a simple program to dispatch to either program randomly, so you end up in the long term with good performance for each.
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hybridtupel
1 hour ago
[-]
Why not run both and use the result retrieved the fastest.
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rdiddly
7 hours ago
[-]
Yeeessss! Microservices!
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chihuahua
3 hours ago
[-]
Your mention of Microservices opened up my mind to additional possibilities. How about we create a microservice for each integer, then deploy 4 billion of them. Send a request to all of them simultaneously. Only one of them will respond with the answer. We still need to decide how to deploy those microservices - one per machine, or multiple per machine?
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layer8
9 hours ago
[-]
You could save stack space by transforming it into a loop. It’s still only O(n)!
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wiz21c
12 hours ago
[-]
Gemini took 4 seconds to answer this prompt: "Here is a number 4200020010101. Think deeply about it and tell me if it is not or or not even."

So if you're concerned with privacy issues, you can run the assembly version proposed in the article locally and be well within the same order of performance.

Let's thank the author of the article for providing a decent alternative to Google.

ah, but the license is not that good we can't reproduce his code.

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brap
11 hours ago
[-]
>Think deeply about it and tell me if it is not or or not even

I think I just experienced a segfault

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sethaurus
10 hours ago
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Why do they call it even when you of in the true number of out false odd the number?
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pksebben
9 hours ago
[-]
Has anyone really been far even as decided to use even go want to do Look more like?
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iberator
8 hours ago
[-]
Hey, why segfault and not stack overflow?
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bdangubic
11 hours ago
[-]
+1
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rossant
10 hours ago
[-]
Nice, that swaps odd and even around.
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classified
10 hours ago
[-]
> if it is not or or not even

Did you want to test the LLM's grammatical comprehension?

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wiz21c
7 hours ago
[-]
When I'm tired my typing goes bad. I obvioulsy meant: "is that number even odd ?" :-)
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moffkalast
9 hours ago
[-]
Finally a problem that Microsoft Phi can ace. Probably. Maybe. Some of the time at least.
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kspacewalk2
4 hours ago
[-]
Surely you mean Microsoft CoPhiLot 365
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xg15
12 hours ago
[-]
> Now, this is a time-memory tradeoff, but my time on this earth is limited so I decided to meta-program the if statements using a programmer program in a different programming language.

  for i in range(2*8):
    if i % 2 == 0:
No comment...
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_ache_
12 hours ago
[-]
Yeah... I come here to talk about that. Should have been

  for i in range(0, 2**8, 2):
      print("    if (number == "+str(i)+")")
      print("        printf(\"even\\n\");")
      print("    if (number == "+str(i + 1)+")")
      print("        printf(\"odd\\n\");")
or

  for i in range(0, 2**8, 2):
      print(f"""    if (number == {i})
          puts("even");
      if (number == {i + 1})
          puts("odd");""")
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NetMageSCW
9 hours ago
[-]
What happens when you try to compute 2**8+1 ?
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amoss
6 hours ago
[-]
If its too large you could just subtract 2*8 and try again.
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iberator
8 hours ago
[-]
Should work fine with long long?
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PurpleRamen
11 hours ago
[-]
I think we can improve this. Just make a microservice who generates the code on the fly and streams it to the compiler. Then you also just have to create the necessary code and don't waste the SSD with unused code-paths.
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travisgriggs
8 hours ago
[-]
I’m disappointed there is no docker image for this. How will I test it out?
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PurpleRamen
7 hours ago
[-]
Microservice kinda implies usage of a container for me. How else would we google-scale it to serve all requests in parallel?

But thinking about, we probably have to use some more microservices, we can't put all that burden on the requester. So a dedicated service for compiling and executing in sandboxes would be necessary. Also, some local load balancers to control the flow and filter out the useless answers. So I'm not an expert on that devops-magic, but I guess this means ~12.5 billion pods fast enough result. Do Amazon or Google offer planetary scale for services?

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cowsandmilk
12 hours ago
[-]
How horridly inefficient, he should have just flipped a Boolean on each iteration.
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kroolik
12 hours ago
[-]
Horridly inefficient. Just unfold the loop.
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projektfu
11 hours ago
[-]
Just output odd and even for each pass and increment by two. Need to make sure you have the right starting value, and check for off-by-one errors.
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layer8
9 hours ago
[-]
It should have used a flag that is being toggled.
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catigula
7 hours ago
[-]
Claude's version:

  even, odd = "even", "odd"
  for i in range(2\*32):
      print(f'    if (number == {i}) puts("{even}");')
      even, odd = odd, even
As usual, a non-marginally superior mind to commentators.
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mring33621
9 hours ago
[-]
I recently asked a Qwen model to write me some code to remove errant spaces ("c he es e" instead of "cheese") in OCR'd text. It proceeded to write 'if' blocks for every combo of all English words and all possible errant spaces. I did not wait for it to finish...
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travisgriggs
8 hours ago
[-]
I see this is 2023… the article refs GPT even then. Can’t believe it’s already that much time gone by, still seems like “last years big news”

I was gonna comment “this is what I really like to see on HN”. Then I saw the date and was sad that we’re having to dip into the history box to find fun/interesting articles more often of late it seems.

Anyone else interested in a temporary moratorium on all things LLM? We could have GPT-free-Wednesday, or something like that :)

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virgilp
8 hours ago
[-]
Definitely not a visionary. This is how you do it in 2025: https://imgur.com/rWiP90P
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bigstrat2003
4 hours ago
[-]
> Anyone else interested in a temporary moratorium on all things LLM? We could have GPT-free-Wednesday, or something like that :)

I would be interested in a permanent moratorium, personally. There's no interesting content to be had in the various LLM articles that litter HN these days. Or failing a topic ban, at least give a way to filter it for those of us who are sick of hearing about AI hype.

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LPisGood
8 hours ago
[-]
> Then I saw the date and was sad that we’re having to dip into the history box to find fun/interesting articles more often of late it seems

We don’t _have_ to. You could start a blog and display the indomitable human spirit.

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orzig
12 hours ago
[-]
If the author is available for consulting I have this bag of rice I need cooked. Should be around 30,000 grains, each needs about 1mL of water and 2m on the stove. Will pay $10 (2025 dollars)
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franciscop
11 hours ago
[-]
Aha, you forgot to specify the country of those "dollars"! For $10 (2025 [Cayman Islands] dollars)! Which is higher than USD10
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867-5309
11 hours ago
[-]
Zimbabwe: 0.027 USD
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Ensorceled
2 hours ago
[-]
I just had flash backs to a previous job where I was brought in to optimize another teams builds since they were now taking minutes instead of seconds.

I tracked it down to a folder with thousands of C++ files called things like uint_to_int.cc and inch_to_cm.cc and cm_to_m.cc. Basically the developer in charge of writing the conversion library took our typed units library and autogenerated a C++ file for every possible conversion the application might need to make.

Every time we added a new typed unit it would create another couple of dozen files to be compiled.

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oneeyedpigeon
11 hours ago
[-]
I prefer data-driven programming, so a simple:

    return odd_or_evenness[n];
works for me, alongside a pretty big array.
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layer8
9 hours ago
[-]
With data-driven programming, I would have expected an SQL table containing all the precomputed results. Unless you carelessly add an index, it has the same asymptotic performance!
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projektfu
11 hours ago
[-]
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Zambyte
9 hours ago
[-]

    const odd_or_evenness = comptime blk: {
        var buf: [16]bool = undefined;
        var is_even = false;
        for (&buf) |*b| {
            b.* = is_even;
            is_even = !is_even;
        }
        break :blk buf;
    };
This looks like a promising strategy.
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enopod_
11 hours ago
[-]
This is the way.
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fainpul
5 hours ago
[-]
Any good engineer knows there is no "best" solution, only tradeoffs.

Save space.

  def even_flip_flop(number):
    even = True
    for _ in range(number):
      even = not even
    return even

Ditto. Sure, this overflows the stack, but you look cool doing it.

  def even_recursive(number):
    return True if number == 0 else not even_recursive(number - 1)

Save time. Just buy more RAM.

  table = [True, False] * 1000  # adjust to your needs
  def even_lookup(number):
    return table[number]
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bobbylarrybobby
4 hours ago
[-]
You can combine the second and third strategies to hit the sweet spot of time and space.
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dorianmariecom
3 hours ago
[-]
i tried in ruby up to 1 million (1 billion was taking too long)

    File.write("check.rb", (["if i == 0\n  puts :even"] + (1..1_000_000).map { |i| "elsif i == #{i}\n  puts :#{i % 2 == 0 ? "even" : "odd"}" } + ["end\n"]).join("\n"))
and added at the top

    i = ARGV.first.to_i
but i'm getting SIGILL

    fish: Job 1, 'ruby check.rb 0' terminated by signal SIGILL (Illegal instruction)
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sedatk
2 hours ago
[-]
Ooh a new bug.
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jagged-chisel
11 hours ago
[-]
I have never seen anyone argue for a ‘switch’ version.

    switch (v) {
     case: 0,2,4,8,…:
       return EVEN;
     case: 1,3,5,7,…:
       return ODD;
     default:
       return IDK;
    }
Slightly less code to generate.
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willguest
11 hours ago
[-]
you forgot the logic to strip the final digit and assign it to v.

processing the whole number is absurd

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pkaeding
10 hours ago
[-]
I think the idea is to fill in the ellipses with even/odd numbers, up to 4B.

You know, to save the performance cost of processing the input as a string, and chomping off all but the last character.

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mgaunard
10 hours ago
[-]
Converting to decimal is just as absurd.

All you need is the final binary digit, which incidentally is the most optimal codegen, `v & 1`.

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71bw
10 hours ago
[-]
Look at Mr. Rocket Scientist over here...
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avandecreme
4 hours ago
[-]
This reminds me of when I learned to program on my casio calculator.

There was a function to detect a key press which would return a number identifying the pressed key.

I needed to map that number to the letter printed on the key to print it on the screen. I don't remember whether there was no hashmap data structure or I just didn't know about it, but I implemented it with a serie of if.

The problem with that solution is that while mapping A was fast, Z was very slow because it was at the end of the list. That is how I discovered divide and conquer/ dichotomy with if branches.

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rossdavidh
6 hours ago
[-]
Really if you are not making custom silicon for this problem, you are just wasting our time here aren't you.
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robotguy
5 hours ago
[-]
I mean, this is the ultimate domain for Quantum Computers:

"Is it odd or Even?"

"YES"

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lubujackson
7 hours ago
[-]
God help us if that code ever makes it's way onto npm.

isEven is a performant, hand-compiled evenness checker for any 32 bit integer. A single file import that does one job and one job only!

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not-so-darkstar
6 hours ago
[-]
it follows the UNIX philosophy of doing one thing and donig it well.
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thewisenerd
13 hours ago
[-]
discussed 2 years ago,

https://news.ycombinator.com/item?id=38790597

4B If Statements (469 comments)

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unwind
13 hours ago
[-]
Meta: Yeah, this should have a "(2023)" tag in the title. Thanks.
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isoprophlex
13 hours ago
[-]
> Visionary genius Ross van der Gussom

Thanks for making me doubt myself & googling who that guy who made python was again, because surely "van der Gussom" isn't a normal Dutch name. Well played.

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mcny
11 hours ago
[-]
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rplnt
1 hour ago
[-]
Can't you just implement javascript interpreter and import is-even package like normal developers?
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SiempreViernes
13 hours ago
[-]
> As a side note, the program is amazingly performant. For small numbers the results are instantaneous and for the large number close to the 2^32 limit the result is still returned in around 10 seconds.

Amazing!

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tanseydavid
7 hours ago
[-]
This line from the article -- I will be laughing about it for days.
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pcthrowaway
23 minutes ago
[-]
> As a side note, the program is amazingly performant. For small numbers the results are instantaneous and for the large number close to the 2^32 limit the result is still returned in around 10 seconds.

Lol

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zkmon
5 hours ago
[-]
Infact, some really performant code such as glMatrix.js do not use any for loops for matrix math, just to allow the javascript engine to optimize the code as much as possible.

https://github.com/toji/gl-matrix/blob/master/dist/gl-matrix...

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KeplerBoy
12 hours ago
[-]
kind of expected gcc to see right through the 300 gigs of code and compile it down to the tenish instructions.
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bspammer
11 hours ago
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They disabled optimisations:

> Lets compile the code, disabling optimizations with /Od to make sure that the pesky compiler doesn’t interfere with our algorithm

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bluGill
9 hours ago
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I would have wanted to see them look at the assembly from various optimization levels to see if the compiler really did. Ideally o1 or something wouldn't see through this but would generate better code in other ways. Disabled optimizations often are really stupid about how they code gen.
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oneeyedpigeon
11 hours ago
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> disabling optimizations with /Od

And that weird flag is because it's a windows compiler: cl.exe, not gcc.

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encom
10 hours ago
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I'm curious what GCC would do if it wasn't purposely lobotomised and fed 300 GB of this nuclear waste.
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encom
9 hours ago
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Well I created the 16 bit .c file, because I'm not that curious. gcc -O0 completed immediately and made a 1,5MB executable. -O1 took about 10 minutes for a 1,8 MB executable. -O2 has been running for 1h15m so far... i7-14700K

I'm in too deep now, so I'll let it run while I'm at work.

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KeplerBoy
4 hours ago
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Keep us updated.
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encom
2 hours ago
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GCC -O2 made a 1,8 MB executable after a bit over four hours. I'm not trying -O3 :D

I don't know enough about compilers to answer why this doesn't get optimised down to something tiny, or why it took so long. I'm not sure what we've learned tonight, but there you go.

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quux
2 hours ago
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I kept waiting for the payoff to be "The optimizer reduced the entire series of if statements to a single instruction"
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SatvikBeri
6 hours ago
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> How did I do this? Well I jumped online, using a mix of my early life experience coding emulators and hacking and looked into the x86(-64) architecture manuals to figure out the correct opcodes and format for each instruction. … Just kidding, that’s horrible. I asked ChatGPT

Ok but if you do want to play with writing binary code manually I recommend Casey Muratori's performance course

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whynotmaybe
12 hours ago
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> I decided to implement this in the C programming language as it’s by far the fastest language on the planet to this day (thanks to the visionary genius Dennis Richie)

Am I lost? Aren't the compiler/linker responsible for fast code, not the language itself?

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bluGill
9 hours ago
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There are language issues as well. 99% of C programs are valid C++, and if you compile with a C++ compiler instead of a C++ compiler will be slightly faster! C++ ha a stronger type system and so once in a while (very rarely) those C programs compile but give incorrect results since C++ allowed the optimizer to make an assumption that wasn't true. Fortran is often even faster because the language allows for even more assumptions. I don't know where Rust fits in here (Rust is hurt today because the better optimizes are designed for C++ and so don't take advantage of extra assumptions Rust allows - it was designed to allow different assumptions from C++ and likely could be better would a ground up optimizer but that would take a large team a decade+ to write: expensive)

Most of the difference in speed is the optimizer/linker. Assuming a fair competition the difference between Ada, C, C++, D, Fortran, Rust, Zig (and many others I can't think of) is very rarely even 1% in any real world situation. Of course it isn't hard add pessimization to make any language lose, sometimes accidentally, so fair competitions are very hard to find/make.

Then again, the article was clearly sarcastic.

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rcxdude
11 hours ago
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Both, usually. A language's semantics can limit how much a compiler can speed up the language. Python, for example, is extremely difficult to make fast due to the fact that almost everything has the semantics of a hashmap lookup. C, in comparison, has relatively little in it that can't be mapped fairly straightforwardly to assembly, and then most of it can be mapped in a more difficult way to faster assembly.
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mbivert
11 hours ago
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> I decided to use the slowest language on the planet, Python (thanks to the visionary genius of Ross van der Gussom).

given the article, it's fair to assume the author was joking around

that being said, the way the language is used and its ecosystem do contribute to the executable's efficiency. yet, given C's frugality, or the proximity between its instructions and the executed ones, it's not unfair to say that "C is fast"

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reedf1
12 hours ago
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It's a wild statement for a few reasons; your observation is one of them.
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croes
12 hours ago
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People often use language as synonym for the whole ecosystem including compiler and linker
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philippta
12 hours ago
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> I saw from the SSD was around 800 MB/s (which doesn’t really make sense as that should give execution speeds at 40+ seconds, but computers are magical so who knows what is going on).

If anyone knows what’s actually going on, please do tell.

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ricardo81
11 hours ago
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Presumably after the first run much or all of the program is paged into OS memory
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tomtomtom777
10 hours ago
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Yes, or it was still in memory from writing.

The numbers match quite nicely. 40gb program size minus 32gb RAM is 8gb, divided by 800mb/s makes 10 seconds.

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hellzbellz123
11 hours ago
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I'm not entirely sure but could it be predictive branching?
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asgs
1 hour ago
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no but thank you. i will stick to using npm's is-odd and is-even packages
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mgaunard
10 hours ago
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A much cooler approach would have been to generate the ASM from the same program, rather than generate a file from python and load that file from C++. The multi-stage build and filesystem are completely unnecessary.

The technique actually has a lot of practical applications, so it's useful to have a C++ library that helps you with generating amd64 machine code.

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runtimepanic
7 hours ago
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The interesting part isn’t the if-statement count but how quickly the compiler and branch predictor erase the differences. It’s a nice demo of why “manual cleverness” rarely beats modern toolchains.
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almosthere
5 hours ago
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If you were to convert an llm model into code, it would have like 500 billion if statements like that
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1a527dd5
11 hours ago
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I love "stupid" stuff like this; you normally learn something small and seemingly inane. It's fun!
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riwsky
9 hours ago
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Would be more maintainable if they injected the loading strategy to be used as a dependency from config instead of hardcoding it :/
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layer8
9 hours ago
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This is also a nice approach for FizzBuzz in leetcode interviews.

Moreover, interviewers will be smitten by the hand-optimized assembly code.

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taylorallred
5 hours ago
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Meanwhile:

    not     eax
    and     eax, 1
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tomaskafka
10 hours ago
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Oh, I have an idea for better leftpad implementation, let me publish that to npm real quick!
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nonethewiser
8 hours ago
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Configuration over logic. At a new scale enabled by AI.
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tigranbs
12 hours ago
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This reminds me of my personal "prime number" grabber research https://github.com/tigranbs/prime-numbers I needed to create the unique graph nodes and assign prime numbers, and to make things efficient, I thought, why not just download the list of known prime numbers instead of generating them one by one. So I did and compiled everything with a single Go binary. Ehh, good old days with a nice feith in making "the best" crappy software out there.
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wvbdmp
12 hours ago
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Next put them in a tree for faster lookups.
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wiz21c
12 hours ago
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With a tree you'll be limited by the RAM. I advise to use a database.
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actionfromafar
11 hours ago
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Map reduce, cluster geo-failover and CDN caching for optimized coldstarts in case you have to bring it up from scratch in a new datacenter. Bio for contact info, hourly billing. I have helped many startups reach their first 100MARR. Buy my audiobook.
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roguecoder
5 hours ago
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Don't forget to create an index on the composite key [number, is_even]!
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d--b
12 hours ago
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Don't reinvent the wheel, put them in a SQLite table, and let the sql engine create the tree for you!
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Exuma
6 hours ago
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This is good stuff
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shevy-java
10 hours ago
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Damn it - my code got leaked!
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ks2048
9 hours ago
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Silly. Don't waste your time on problems other people have already solved! Use JS and "npm install odd_or_even".
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DeathArrow
9 hours ago
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I would also like to praise the visionary genius Ross van der Gussom, without whom this wonderful achievement in software engineering would not have been possible!
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klaff
9 hours ago
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Is he the one married to the singer, Adele Dazeem?
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DeathArrow
7 hours ago
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No, this one is the creator of the mighty programming language Mython.
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tornadofart
10 hours ago
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"The executable is around 2 MB"- Every dotnet programmer: "Those are rookie numbers!"
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nmilo
9 hours ago
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I see why now npm's is-odd has millions of downloads
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ajsnigrutin
10 hours ago
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Why not optimize this? Create a lookup table, a 2^64 large array of bools, and just check the n-th element to see if it's odd or even?

Many gigabytes saved!

/s

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d-lisp
12 hours ago
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if(n&1)

else

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imtringued
12 hours ago
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You can do it even faster with the if statements:

    #include <stdio.h>
    #include <stdlib.h>

    int main(int argc, char *argv[])
    {
        if (argc < 2) {
            fprintf(stderr, "Usage: %s <string>\n", argv[0]);
            return 1;
        }

        char *s = argv[1];
        int i;

        /* find the end of the string */
        for (i = 0; s[i] != '\0'; ++i)
            ;

        /* make sure the string wasn't empty */
        if (i == 0) {
            fprintf(stderr, "Error: empty string\n");
            return 1;
        }

        /* last character is at s[i - 1] */
        char d = s[i - 1];

        if (d == '0')
            printf("even\n");
        if (d == '1')
            printf("odd\n");
        if (d == '2')
            printf("even\n");
        if (d == '3')
            printf("odd\n");
        if (d == '4')
            printf("even\n");
        if (d == '5')
            printf("odd\n");
        if (d == '6')
            printf("even\n");
        if (d == '7')
            printf("odd\n");
        if (d == '8')
            printf("even\n");
        if (d == '9')
            printf("odd\n");
    
        return 0;
    }

gcc -std=c11 -Wall -Wextra -O2 -o check_digit check_digit.c

./check_digit 999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999

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Tistron
12 hours ago
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You can do it even even faster by replacing your if statements (works because the ascii values end in the digit they represent):

    if (d & 1)
       printf("odd\n");
    else 
       printf("even\n")
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d-lisp
9 hours ago
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You inspired me this joyful rewrite:

    #define _(e) { e;};
    #define r(e) _(return e)
    #define I(b, e) _(if (b) r(e));
    #define W(e) _(while (1) _(e));
    int main(int c, char **v) {
      _(I(c != 2, -1) _(c = 0) W(I(!v[1][c++], v[1][c - 2] & 1)))
    }
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tetris11
11 hours ago
[-]
probably easier in bash:

    number="$1"
    if [[ "$number" =~ "^(2|4|6|8|10|12|14|16|18|20)$" ]]; then
        echo even
    elif [[ "$number" =~ "^(1|3|5|7|9|11|13|15|17|19)$" ]]; then
        echo odd
    else
        echo Nan
    fi
A bit limited, but you can scale it up
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wiz21c
12 hours ago
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I'm disappointed, it's not in rust. :-)
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actionfromafar
11 hours ago
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Still hoping for the C++ template version. Don’t pay for what you don’t use!
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ITniggah
3 hours ago
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"If this illegal and the associated family would have been finally deported..."
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